Following the dimensionaly correct equation on wikipedia, you have $$\frac{d^2 u}{d\theta^2}+u=\frac{r_s c^2}{2h^2}+\frac{3r_s}2 u^2$$ with $$r_s=\frac{2G\mu}{c^2}$$ Now $u$ is inverse distance, so in order to make it dimensionless you need to multiply it with a constant with units of distance. The obvious choice would be $r_s$. Then for $x=ur_s$, you multiply the first equation with $r_s$ to get $$\frac{d^2 x}{d\theta^2}+x=\frac{r_s^2 c^2}{2h^2}+\frac 32 x^2$$ All terms are now dimensionless.