As per David's comment, two of your answers (first and last) are wrong. Instead: $$n(A) = 7+4+2+3 = 16 \;\text{ and }\;n((A\cap B)\cup C)= 4+3+2+5+4 = 18.$$
As per David's comment, two of your answers (first and last) are wrong. Instead: $$n(A) = 7+4+2+3 = 16 \;\text{ and }\;n((A\cap B)\cup C)= 4+3+2+5+4 = 18.$$