HINT: Let $M$ denotes male tree, $F$ -- female tree. The probability is $$ 1-P(MMM)-P(FFF). $$ But, from independency, $P(MMM)=P(M)P(M)P(M)=(1/2)^3$.
BTW: What are female trees? Have they a hollow? ;-)
HINT: Let $M$ denotes male tree, $F$ -- female tree. The probability is $$ 1-P(MMM)-P(FFF). $$ But, from independency, $P(MMM)=P(M)P(M)P(M)=(1/2)^3$.
BTW: What are female trees? Have they a hollow? ;-)