cron job to run the Thursday before the second Monday in a month I am trying to write a cron schedule to run a job the Thursday before the second Monday in a month. So far I have this 0 0 8 ? * MON#2 But that runs on the second Monday of the month. Is there a way I can go back four days from that time to the previous Thursday? For example, for September 2016, the second Monday of the month is the 12th of the month. So I would like to schedule this to run the previous Thursday, which would be the 8th of the month.

I don't think you can do that in cron. Maybe with `0 0 * * 4` you should run a script every thursday and in that script, you can check if it is the thursday before the second monday of the month.