Artificial intelligent assistant

recursive and creative theorem How can we show that if A is creative, then A is not recursive. Only thing I can get out is the fact that if A is creative, if it is rec. enumerable and the complement(A) is productive. Thanks

If $A$ is recursive, then the complement($A$) is r.e., let it be $W_{e}$.

According to de definition of the productive set, there is a recsive function $f(x)$ such that:

$W_{x}\subseteq \overline{A}\Longrightarrow (f(x)\downarrow\wedge f(x)\in\overline{A}-W{x})$

The contradiction is quite straightforward: $W_{e}\subseteq \overline{A}$ but $\overline{A}-W_{e}=\emptyset$.

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