The following is a minimalist answer. Let $\triangle ABC$ be right-angled at $C$. Drop a perpendicular from $C$ to $P$ on $AB$. This divides $\triangle ABC$ into two similar right triangles which, without any cutting at all, can be reassembled (without any motion) to make the triangle on the hypotenuse.
If we prefer the figures to be erected "outside" the original triangle, reflect the pieces across the sides.