a) A $\sigma$-algebra is stable under complementation, hence $\\{\Omega\setminus A,A\in\mathcal A\\}=\mathcal A$ (it cannot be equal to $\Omega\setminus \mathcal A$, because $\mathcal A$ is a _class of subsets of $\Omega$_ , while $\Omega$ is a set.
b) Your $\mathcal A$ is not a $\sigma$-algebra (it should at least contain $\Omega$). If $\mathcal A$ is a $\sigma$-algebra with more than two elements, there is $A\in\mathcal A$ which is neither the whole set nor empty. But this is also the case for $\Omega \setminus A$.
c) Consider the counting measure (which assigns to each sets its number of elements if the set if finite, and $+\infty$ otherwise).