Hint: assume wlog that $t>s$. By the Markov property, $$ F(x) = E^x[f(X_t) g(X_s)] = E^x[ h(X_s)g(X_s)], $$ where $h(x) = E^x[f(X_{t-s})]$.
Hint: assume wlog that $t>s$. By the Markov property, $$ F(x) = E^x[f(X_t) g(X_s)] = E^x[ h(X_s)g(X_s)], $$ where $h(x) = E^x[f(X_{t-s})]$.