HINT: Use the fact that $\Bbb R$ has the least upper bound property: if $\varnothing\
e A\subseteq\Bbb R$, and $A$ is bounded above, then $A$ has a least upper bound. If your increasing sequence is $\langle x_n:n\in\Bbb N\rangle$, let $x$ be the least upper bound of $\\{x_n:n\in\Bbb N\\}$, and show using the definitions of _least upper bound_ and _limit of a sequence_ that $x=\lim\limits_{n\to\infty}x_n$.
The proof for the other result is similar. Alternatively, if $\langle x_n:n\in\Bbb N\rangle$ is decreasing and bounded below, then $\langle-x_n:n\in\Bbb N\rangle$ is increasing and bounded above, so by the first result it converges to some $x$. Now show that $\langle x_n:n\in\Bbb N\rangle$ converges to $-x$.
Forgot to say: in my experience it’s usually called the _monotone convergence theorem_.