Since $M/\mathfrak mM$ is an $R$-module of finite length, $\operatorname{reg}(M/\mathfrak mM)=\max\\{i:(M/\mathfrak mM)_i\
e 0\\}$; see here. Now, since $\operatorname{reg}(M)\ge\max\\{j:\beta_{0j}(M)\
e 0\\}$, it follows that $\operatorname{reg}(M)\ge \operatorname{reg}(M/\mathfrak mM)$.