Artificial intelligent assistant

How can I convert X11 keysym to the string that will be typed? I have a keysym number (for example 0x1a2, which is `XK_breve` in `keysymdef.h`, in latin2 charset). Is there a way get a string that will be typed when key emitting that keysym will be pressed? I tried using `XKeysymToString`, but that gives me the full name of the symbol (`breve`) instead of the character that will be typed (`˘`). There's `XLookupString` that does something similar, but it requires XKeyEvent which I don't have (I only have a keysym number).

You should use Xutf8LookupString(3) which will also take into account the input method and xkb rules in effect.

Not all keypresses directly generate a string.

Example:


#include
#include

int main(int argc, char** argv) {

KeySym keysym = 0x1a2;

Display* display = XOpenDisplay(":0");

XIM xim = XOpenIM(display, 0, 0, 0);
XIC xic = XCreateIC(xim, XNInputStyle, XIMPreeditNothing | XIMStatusNothing, NULL);

XKeyPressedEvent event;
event.type = KeyPress;
event.display = display;
event.state = 0;
event.keycode = XKeysymToKeycode(display, keysym);

char buffer[32];
KeySym ignore;
Status return_status;
Xutf8LookupString(xic, &event, buffer, 32, &ignore, &return_status);
printf("%s\
", buffer);

XCloseDisplay(display);
return 0;
}

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