Yes, this is true. Let $C$ denote the cofiber of $i$, and let $T$ be any test spectrum. Then using the retract $r$, we obtain a split short exact sequence $$0 \to [T,E] \to [T,F] \to [T,C] \to 0.$$ Thus we have natural isomorphisms $$[T,F] \cong [T,E] \oplus [T,C] \cong [T, E \vee C].$$ So we have $F \simeq E \vee C$ by the Yoneda lemma.