We assume **independence** of bit errors. This is a somewhat dubious assumption, since errors often occur in bursts.
The probability of erroneous interpretation (or inability to decode) of a codeword of length $6$ is the probability that $2$ or more bits are incorrectly transmitted. The probability that $0$ bits are wrong is $(0.75)^6$. The probability that exactly $1$ bit is wrong is $6(0.25)(0.75)^5$. Add these two numbers, subtract the result from $1$.