> The optimal way to divide 3-space into pieces of equal volume with the least total surface area is the rhombic dodecahedral honeycomb.
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> Is my conjecture right?
No.
It has been described in the paper "A counter-example to Kelvin's conjecture on minimal surfaces" by D. Weaire & R. Phelan (link) that both the Kelvin tetrakaidecahedron and their own structure are closer to a solution to the problem which corresponds to this question. It is called the Kelvin problem and is still an open problem in mathematics.