This is an abuse of notation. It is true that, as you've stated, $L^2$ is not a subset of $\mathcal S'$. What the notation $L^2\subset \mathcal S$ means is that $L^2$ embeds in $\mathcal S'$
This is an abuse of notation. It is true that, as you've stated, $L^2$ is not a subset of $\mathcal S'$. What the notation $L^2\subset \mathcal S$ means is that $L^2$ embeds in $\mathcal S'$