If you assume the axiom of choice, then the existence of a surjection $f:A\to B$ implies an injection $e:B\to A$: for $b\in B$ choose $e(b)\in f^{-1}(b)$. Together with the what you know about injections, this gives you everything you want.
If you assume the axiom of choice, then the existence of a surjection $f:A\to B$ implies an injection $e:B\to A$: for $b\in B$ choose $e(b)\in f^{-1}(b)$. Together with the what you know about injections, this gives you everything you want.