Probability of seating on a toboggan If I have a toboggan, and there are 5 boys, and 2 girls, what is the probability that 4 or more boys are sitting next to each other? What is the answer and how could I solve more like it?

Assuming all 7 children are on the toboggan

the total number of seating arrangements are $\binom 72=21$

Five boys a in a row can be placed among the girls in $\binom 31=3 $ ways

A group of four boys can also be placed among the girls in 3 ways , in each case leaving 2 places to put the remaining boy

So $$P = \frac{3+6}{21} =\frac 37 $$