If solution points $(x; y)$ exist, linearly scaled points $(kx; ky)$ must also be solutions, as no inequality is violated by multiplying both sides with the same factor.
Therefore, we can assert an arbitrary non-zero value for $x$ and calculate the corresponding solution interval for $y$. If the interval is empty, no solution exists.
Example:
$x = 1$
$ay < 1 < by$
$c < y < d$
With known values for $a, b, c, d$ we can immediately see if there exists a feasible value interval for $y$. It cannot be more than one interval as the intersection of two intervals is either empty or one uninterrupted interval.