Find the remainder when $10^4$ is divided by 13. Long division gives $10^4=769\cdot 13+3$. Thus the smallest number larger than $10^4$ which is divisible by $13$ is $$769\cdot 13+13=(769\cdot 13+3)+10=10^4+10.$$
Find the remainder when $10^4$ is divided by 13. Long division gives $10^4=769\cdot 13+3$. Thus the smallest number larger than $10^4$ which is divisible by $13$ is $$769\cdot 13+13=(769\cdot 13+3)+10=10^4+10.$$