Set $$x(t) = C_1(t) x_1(t),$$ where $x_i(t) = e^{s_i t}$, $s_i = \\{1,4\\}$ (you can chose any of the roots). Differentiate now to obtain $x'$ and $x''$ and substitute back into the original ODE. Take into account that $x_1'' - 5x_1'+ 4x_1 = 0$ and solve for $C_1$.
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