If $(x,y)$ is a point on that locus, then the condition you are given is that $x-(-8) = x+8$ (the distance to the directrix) is twice $\sqrt{(x+2)^2+y^2}$ (the distance to the focus). So if you set those two equal, square the resulting equation and simplify, you will get what looks like a reasonable equation for the locus. You can apply the same approach for your second question.