is a serie geometric So $$\sum_{i=0}^{\infty}3*0.3^{i}=3\sum_{i=0}^{\infty}0.3^{i}=3\cdot\frac{1}{1-0.3}$$ so is equal
$$\sum_{i=0}^{\infty}3*0.3^{i}=\frac{30}{7}\approx 4.28571428571$$
is a serie geometric So $$\sum_{i=0}^{\infty}3*0.3^{i}=3\sum_{i=0}^{\infty}0.3^{i}=3\cdot\frac{1}{1-0.3}$$ so is equal
$$\sum_{i=0}^{\infty}3*0.3^{i}=\frac{30}{7}\approx 4.28571428571$$