HINT: Representing the six colors by the numbers $1$ through $6$, we see that the following arrangements are equivalent:
$$\begin{bmatrix}1&2&3\\\4&5&6\end{bmatrix}\qquad\begin{bmatrix}3&2&1\\\6&5&4\end{bmatrix}\qquad\begin{bmatrix}4&5&6\\\1&2&3\end{bmatrix}\qquad\begin{bmatrix}6&5&4\\\3&2&1\end{bmatrix}$$
The first is the original; the second is flipped about the vertical axis; the third is flipped about the horizontal axis; and the last is rotated $180^\circ$ degrees (or flipped about each of the axes).
What _should_ you divide by?