Alright, so let's take $u$ to be the upper bound. Lets make $l$ the lower bound. When you go to the right, the percentage of the area swept from x=0 to some $x$ the right is:
$$\frac{x}{u}\times 100\%$$
Similarly, on the left you'll just use your lower bound. You don't even need absolute value because the negatives will cancel:
$$\frac{x}{l}\times 100\%$$
Let me know if that's what you meant.