If you read Greiner closely, $f(x)$ has period $1$ because that's how it is constructed.
$a_0=0$ because $a_0=\int_{0}^{1}f(u)du=0$
If you read Greiner closely, $f(x)$ has period $1$ because that's how it is constructed.
$a_0=0$ because $a_0=\int_{0}^{1}f(u)du=0$