Artificial intelligent assistant

No minimal imperfect graph of order 200 Prove that there is no minimal imperfect graph of order 200, without using the Strong Perfect Graph Theorem.

It is well-known that for a p-critical graph $|G|=\alpha(G)\omega(G)+1$ (where $\alpha$ is the independence number and $\omega$ the clique number) and that they have both $\alpha(G)$ and $\omega(G)$ at least 2. Since 199 is prime this is a contradiction. Do you need proofs of any of the statements (they are not very hard)?

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