As mfl commented, a linear fit $y=a+bx$ looks more appropriate than $y=ae^{bx}$.
For the linear model, as already given by mfl, we should get $$y=76.6228+0.0944818 x\qquad SSQ=7363.8\qquad R^2=0.995485$$
Because of the curvature for low values of $x$, a better fit could be obtained using $y=a+bx^c$. For such a case $$y=37.6705+0.57678 x^{0.804092}\qquad SSQ=485.984\qquad R^2=0.999702$$ which is definitively much better.