Algebra Puzzle Question > Julia drives to her holiday destination over a period of five days. On the first day she travels a certain distance, on the second day she travels half that distance, on the third day a third of that distance, on the fourth day one quarter of the distance and on the fifth day one fifth of the distance. If her destination is $1000$ km away, write an equation and solve it to find how far she travels on the first day to the nearest kilometre. A textbook question from my exercise. The textbook solution is $438$ km. **My attempt** Let distance travelled on the first day $= x$ Then $x+x/2+x/6+x/24+x/120=1000$ $(103/60)x=1000$ $x=583$ Therefore distance travelled on the first day is $583$ km. Is the mistake in my working or is the textbook solution provided incorrect?

$$x+x/2+x/3+x/4+x/5=1000$$

$$x=437.95$$

I think now you will understand where you mistaken.

Hope it will help you.

Nice attempt.