Well, not very surprisingly, this is true for any algebraic extension. If $ L/K $ is an algebraic extension of fields, then $ L = \cup_{x \in L} K(x) $, and each $ K(x) $ is finite over $ K $ since $ x \in L $, and $ L $ is algebraic over $ K $.
Well, not very surprisingly, this is true for any algebraic extension. If $ L/K $ is an algebraic extension of fields, then $ L = \cup_{x \in L} K(x) $, and each $ K(x) $ is finite over $ K $ since $ x \in L $, and $ L $ is algebraic over $ K $.