No. The fundamental group of $SO(n)$ is $\Bbb Z/2$, so its universal cover is just a double cover. Indeed, what this is saying is that $Spin(n)$ is simply connected.
No. The fundamental group of $SO(n)$ is $\Bbb Z/2$, so its universal cover is just a double cover. Indeed, what this is saying is that $Spin(n)$ is simply connected.