$$2P=Pe^{.056t}$$ Dividing by P gets me $$2=e^{.056t}$$ Now to undo the exponent, you take the natural log, ln, of each side... $$\ln{2}=\ln{e^{.056t}}=.056t$$ Can you take it from here?
$$2P=Pe^{.056t}$$ Dividing by P gets me $$2=e^{.056t}$$ Now to undo the exponent, you take the natural log, ln, of each side... $$\ln{2}=\ln{e^{.056t}}=.056t$$ Can you take it from here?