The chance of anding on A for one spin is $\frac{90+45}{360}=\frac{3}{8}$. So the probability of that happening twice in a row is $\frac{3}{8}\times\frac{3}{8}=\frac{9}{64}$.
The chance of anding on A for one spin is $\frac{90+45}{360}=\frac{3}{8}$. So the probability of that happening twice in a row is $\frac{3}{8}\times\frac{3}{8}=\frac{9}{64}$.