Let $X$ be one component of $G-v$ and $Y$ the rest of $G-v$. There are no edges between $X$ and $Y$ in $G$, so in $G'$ every vertex in $X$ is connected to every vertex in $Y$.
This means that $G'-v$ contains a complete bipartite graph, i.e. it is certainly connected, so $v$ cannot be an articulation vertex in $G'$.