No, simply let $F(x) = -2Ax$ when $||2Ax||\leq \gamma$ (and 0 otherwise) and you will always have a negative definite quadratic locally somewhere.
No, simply let $F(x) = -2Ax$ when $||2Ax||\leq \gamma$ (and 0 otherwise) and you will always have a negative definite quadratic locally somewhere.