The "literal" translation would be $$\exists x\ (D(x)\wedge \
eg R(x))\ .$$ This is equivalent to $$\
eg\forall x\ (\
eg D(x)\vee R(x))$$ or $$\
eg\forall x\ (D(x)\to R(x))\ ,$$ but not to the answer they gave.
The "literal" translation would be $$\exists x\ (D(x)\wedge \
eg R(x))\ .$$ This is equivalent to $$\
eg\forall x\ (\
eg D(x)\vee R(x))$$ or $$\
eg\forall x\ (D(x)\to R(x))\ ,$$ but not to the answer they gave.