If you draw a Venn diagram it becomes apparent that
$$\Pr(N\cap F^c) = \Pr(N) - \Pr(N\cap F) =.54-.28=.26,$$
where $N$ is today, $F$ is the future, and $^c$ their complements.
If you draw a Venn diagram it becomes apparent that
$$\Pr(N\cap F^c) = \Pr(N) - \Pr(N\cap F) =.54-.28=.26,$$
where $N$ is today, $F$ is the future, and $^c$ their complements.