Another way to think about this is to realize that the casino must choose $5$ balls from the $10$ that you chose and $15$ balls from the $70$ that you didn't choose. So: $$P = \frac{\binom{10}{5} \binom{70}{15}}{80\choose 20} \approx 0.0514...$$
Another way to think about this is to realize that the casino must choose $5$ balls from the $10$ that you chose and $15$ balls from the $70$ that you didn't choose. So: $$P = \frac{\binom{10}{5} \binom{70}{15}}{80\choose 20} \approx 0.0514...$$