After some discussion, it seems like your question is actually the following:
> Let $\omega$ be a differential form and $c \in \mathbb{R}$. Is $\star(c\omega) = c(\star\omega)$?
The answer to this is yes. The Hodge dual is real-linear, in fact it is linear over real-valued functions, i.e. $\star(f\omega) = f(\star\omega)$.
If you want to bring out a complex number or complex-valued function, then it depends on your definition of $\star$; in particular, whether it is complex linear or conjugate linear.