How would you find the probability of selecting 3 red marble and 2 green marble or 1 yellow marble and 2 orange marble out of a bag of 12 marbles How would you find the probability of selecting 1 red marble and 1 green marble or 1 yellow marble and 1 orange marble out of a bag of 12 marbles There are four red marbles,one green marble, one yellow marble, six orange marbles

In this answer I'm assuming that the asker means to find the probability of the cases combined, and that the order in which he listed the marbles is the order that they are picked:
The probability of picking a red marble is $4/12$. The probability of picking a green marble is $1/11$, since I'm assuming that the marbles are not replaced. You multiply since you want both of these occuring. $1/3$ times $1/11$ equals $1/33$.
Try to apply this logic to the orange and yellow marbles, then multiply the results.