Yes, your reasoning is correct.
Alternatively we want the probability of choosing $2$ of $8$ Pike residents when choosing $2$ of $18$ total residents.
We have
$$\frac{8 \choose 2}{18 \choose 2}\approx0.183$$
Yes, your reasoning is correct.
Alternatively we want the probability of choosing $2$ of $8$ Pike residents when choosing $2$ of $18$ total residents.
We have
$$\frac{8 \choose 2}{18 \choose 2}\approx0.183$$