Odd minute Probabililty During a soccer match of 90 minutes there are 30 fouls on average. How can I calculate the probability of at least one foul at minute x and the probability of at least a foul to happen on an odd minute?

If you have an average of 30 fouls in 90 minutes, then the rate of fouls per minute is $\lambda = 1/3,$ as @N74 says. Then the probability of at least one foul in a _particular_ minute is $$P(X \ge 1) = 1 - P(X=0) = 1- e^{-1/3} = 0.2835,$$ where $X \sim \mathsf{Pois}(\lambda = 1/3).$ In R statistical software:


1 - dpois(0, 1/3)
## 0.2834687


I have no idea what you mean by at least one foul in an 'odd minute'. Is that a separate problem? Or somehow tangled up with the first part about minute `x`? If you mean any odd numbered minute during 90 minutes, unrelated to the above, the rate for that would be $\lambda = 15.$ I'll let you do the rest, depending on what you mean.