How to determine callee function name in a script To make it short, doing something like: -bash$ function tt { echo $0; } -bash$ tt `$0` will return `-bash`, but how to get the function name called, i.e. `tt` in this example instead?

In `bash`, use FUNCNAME array:


tt() {
printf '%s\
' "$FUNCNAME"
}


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With some `ksh` implementations:


tt() { printf '%s\
' "$0"; }


In `ksh93`:


tt() { printf '%s\
' "${.sh.fun}"; }


From `ksh93d` and above, you can also use `$0` inside function to get the function name, but you must define function using `function name { ...; }` form.

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In `zsh`, you can use `funcstack` array:


tt() { print -rl -- $funcstack[1]; }


or `$0` inside function.

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In `fish`:


function tt
printf '%s\
' "$_"
end