If we only consder the independent(!) possibilities of the wird BANANA occuring within the first six letters, or within the second six lettres (i.e.,m positions 7 to 12), or within the third six letters (13 to 18), or ..., then we note that it occurs aeady in each of these positions with a constant positive probability $p=\frac1{26^6}$. The probability that the word does _not_ occur within the first $6n$ letters is therefore at most $(1-p)^n$. By letting $n\to \infty$, we see that the probability that BANANA does not occur at all in the infinite letter sequence is zero. By the same argument, for any fixed $m$, the probability that the word occurs at most $m$ times within the first $6n$ letters tends to $0$ as $n\to \infty$, i.e., the probability of at most $m$ occurrences in the infinite string is zero. Consequently, the probability of infinitely many occurrences is one.