Lemma 1 states that if $E_1,E_2,\ldots,E_n$ are disjoint measurable subsets of a finite-measure set $E$, then for a simple function $\phi = \sum_ia_i \cdot \chi_{E_i}$ it follows that
$$\int_E \phi = \sum_{i=1}^n a_i \cdot m(E_i).$$
The proof invokes the definition of the integral of a simple function in terms of the canonical representation, $\phi = \sum_i\lambda_i \cdot \chi_{A_i},$ where the $\lambda_i$'s are distinct and the $A_i$'s are disjoint. The assumption that the $E_i$'s are disjoint is needed because the proof relies on the fact that each set $A_i$ is a disjoint union with measure
$$m(A_i) = \sum_j m(E_{i_j}).$$
However, once you prove linearity of the integral, in general, the conclusion of the lemma is immediate regardless of whether the $E_i$'s are disjoint or not, i.e.
$$\int_E \phi = \int_E\sum_{i=1}^n a_i \cdot \chi_{E_i}= \sum_{i=1}^n a_i \cdot \int_E \chi_{E_i}= \sum_{i=1}^n a_i \cdot m(E_i).$$