No, consider $C = \\{ c \subseteq \mathbb N \mid 0 \in c \\}$. $C \subseteq \mathcal P(\mathbb{N})$ is closed under unions and intersections (hence monotone) but not under complements, since $\mathbb N \setminus \\{0\\} \
ot \in C$.
No, consider $C = \\{ c \subseteq \mathbb N \mid 0 \in c \\}$. $C \subseteq \mathcal P(\mathbb{N})$ is closed under unions and intersections (hence monotone) but not under complements, since $\mathbb N \setminus \\{0\\} \
ot \in C$.