I presume that you speak about distributions on the Borel $\sigma$-algebra $\mathcal B(\mathbb R)$. In terms of cardinality, there are quite few of them, namely, $\mathfrak{c} = |\mathbb{R}|$. Indeed, each probability distribution $\mathcal B(\mathbb R)$ is uniquely determined by its values on the intervals $(-\infty,q)$ with $q\in\mathbb{Q}$. Therefore, the number of probability measures does not exceed the number of sequences of real numbers, which is $\mathfrak{c}$. Since, obviously, there are both $\mathfrak{c}$ distributions with finite and infinite variance, so your guess is wrong.
There are other ways to compare sets, e.g. in terms of the Baire categories. If we consider the weak convergence topology, then both finite variance and infinite variance sets are easily shown to be second category, so another draw here.
Overall, I see no reason to believe that there are fewer finite variance (or finite expectation or finite exponential moment) distributions than others.