Hint: This question uses permutations.
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> There are 12 people and there are three distinguishable positions. You have 12 choices for the first position. Then you have 11 choices for the second position. Finally, once you have selected the other two, you have 10 people left for the last position. Hence, there are $12\cdot 11\cdot 10 = 1320$ ways to select the the committee/group.