You're correct about all of the definitions, but your conclusions are not true. Let $A$ be our set, and take $R$ to be _any_ subset of $\Delta_A = \\{(a,a) \mid a\in A\\}$. This is a relation which is both symmetric and antisymmetric, but is not reflexive, since there's no reason to suggest that it is all of $\Delta_A$.
As a concrete example, take $A=\\{1,2,3\\}$ and $R=\\{(1,1)\\}$. It is clearly symmetric, and it trivially satisfies anti-symmetry.