Differing notations for the distribution seem to be in play.
Their answer is for $\mathcal N(\mu{:=}{-8}, \sigma^2{:=}4)$. You have used $\mathcal N(\mu{:=}{-8}, \sigma{:=}4)$.
$$\phi\left(\tfrac{-5+8}{2}\right)\approx 0.933$$
Differing notations for the distribution seem to be in play.
Their answer is for $\mathcal N(\mu{:=}{-8}, \sigma^2{:=}4)$. You have used $\mathcal N(\mu{:=}{-8}, \sigma{:=}4)$.
$$\phi\left(\tfrac{-5+8}{2}\right)\approx 0.933$$