Let $P$ denote the event that person A is chosen for president and let $T$ denote the event that person A is chosen for treasurer.
Then the events $P$ and $T$ are mutually exclusive so that:$$\Pr(P\cup T)=\Pr(P)+\Pr(T)=\frac1{20}+\frac1{20}=0.1$$
Let $P$ denote the event that person A is chosen for president and let $T$ denote the event that person A is chosen for treasurer.
Then the events $P$ and $T$ are mutually exclusive so that:$$\Pr(P\cup T)=\Pr(P)+\Pr(T)=\frac1{20}+\frac1{20}=0.1$$